PTHH: CuO +2 HCl -> CuCl2 + H2O (1)
x________________2x___x___x(mol)
ZnO + 2 HCl -> ZnCl2 + H2O (2)
y____2y__________y____y(mol)
Ta có: nHCl= 0,15.2=0,3(mol)
nHCl(1) + nHCl (2)= 0,3(mol)
<=> 2x +2y=0,3 (a)
Ta có: mCuO+ mZnO= 12,1
<=> 80x+81y=12,1 (b)
Từ (a),(b) Ta có hpt:
\(\left\{{}\begin{matrix}2x+2y=0,3\\80x+81y=12,1\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0,05\\y=0,1\end{matrix}\right.\)
=> mCuO= 0,05.80= 4(g)
%mCuO= (4/12,1).100\(\approx33,058\%\)
=> %mZnO\(\approx100\%-33,058\%=66,942\%\)
* PTHH: CuO + H2SO4 -> CuSO4 + H2O
0,05______________0,05___0,05___0,05(mol)
ZnO + H2SO4 -> ZnSO4 + H2O
0,1____0,1__________0,1__0,1(mol)
=> mH2SO4= (0,05+0,1).98= 14,7(g)
=> mddH2SO4(20%)= 73,5(g)
