\(m_{HCl}=\dfrac{124,1\cdot25}{100}=31,025g\)
\(\Rightarrow n_{HCl}=0,85mol\)
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)
x 3x
\(Zn+2HCl\rightarrow ZnCl_2+H_2\)
y 2y
\(\Rightarrow\left\{{}\begin{matrix}27x+65y=17,05\\3x+2y=0,85\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=0,15\\y=0,2\end{matrix}\right.\)
\(\%m_{Zn}=\dfrac{0,2\cdot65}{17,05}\cdot100\%=75,25\%\)