Na2O + H2O \(\rightarrow\)2NaOH
0,05__________0,1____________(mol)
nNa2O= 3,1:62=0,05 (mol)
\(\rightarrow\) CmNaOH\(\frac{0,1}{2}\)= 0,05M
2NaOH + H2SO4\(\rightarrow\) Na2SO4 + 2H2O
0,1______0,05
mdd=\(\frac{\text{0,05.98.100}}{20}\)= 24,5 (g)
Na2O+H2O->2NaOH
0,05 0,1
nNa2O=3,1/62=0,05(mol)
CMNaOH=0,1/2=0,05(M)
b)
2NaOH+H2SO4->Na2SO4+2H2O
0,1 0,05
mddH2SO4=0,05x98/20%=24,5(g)