Question

giúp

Answer 1

\(A=\left|2x-\frac{3}{5}\right|+1\left(3\right)\)

Vì \(\left|2x-\frac{3}{5}\right|\ge0\Rightarrow\left|2x-\frac{3}{5}\right|+1,\left(3\right)\ge0+1,\left(3\right)=1,\left(3\right)=\frac{4}{3}\)

\(\Rightarrow A\ge\frac{4}{3}\)

\(\Rightarrow MIN_A=\frac{4}{3}\Leftrightarrow\left|2x-\frac{3}{5}\right|=0\Leftrightarrow2x-\frac{3}{5}=0\Leftrightarrow2x=\frac{3}{5}\Leftrightarrow x=\frac{3}{10}\)

Vậy MIN_A=\(\frac{4}{3}\) khi \(x=\frac{3}{10}\)

Answer 2

4/3