Question

Giúp với ạ! =)

Answer 1

Xét tứ giác AEIF có:

\(\widehat{A}+\widehat{AEI}+\widehat{AFI}+\widehat{EIF}=360^0\)

\(\Rightarrow\widehat{EIF}=360^0-\widehat{A}-\widehat{AFI}-\widehat{AEI}=360^0-60^0-90^0.2=120^0\)

\(\Rightarrow x=180^0-\widehat{EIF}=180^0-120^0=60^0\)(kề bù)

Answer 2

=)