= \(\dfrac{2.5.5^{21}-9.5^{21}}{\left(5^2\right)^{10}}:\dfrac{5\left(3.7.7^{14}-19.7^{14}\right)}{7.7^{15}+3.7^{15}}\)
= \(\dfrac{\left(10-9\right).5^{21}}{5^{20}}:\dfrac{5\left(21-19\right).7^{14}}{\left(7+3\right).7^{15}}\)
= \(\dfrac{5^{21}}{5^{20}}:\dfrac{5.2.7^{14}}{10.7^{15}}\)
= \(5:\dfrac{1}{7}\)
= 35
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\(=\dfrac{5^{21}\cdot1}{5^{20}}:1=5\)
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