\(\left(3-\dfrac{b-\sqrt{b}}{\sqrt{b}-1}\right)\left(3+\dfrac{b+\sqrt{b}}{1+\sqrt{b}}\right)=\left(3-\dfrac{\sqrt{b}\left(\sqrt{b}-1\right)}{\sqrt{b}-1}\right)\left(3+\dfrac{\sqrt{b}\left(\sqrt{b}+1\right)}{1+\sqrt{b}}\right)=\left(3-\sqrt{b}\right)\left(3+\sqrt{b}\right)=9-b\)
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