a, Ta có: \(\dfrac{6}{15}-\dfrac{1}{10}=\dfrac{2}{5}-\dfrac{1}{10}=\dfrac{4}{10}-\dfrac{1}{10}=\dfrac{3}{10}< 1\)
\(\Rightarrow\dfrac{6}{15}-\dfrac{1}{10}< 1\)
b, Ta có:\(\dfrac{12}{18}-\dfrac{1}{6}=\dfrac{4}{6}-\dfrac{1}{6}=\dfrac{3}{6}=\dfrac{1}{2}>\dfrac{1}{3}\)
\(\Rightarrow\dfrac{6}{15}-\dfrac{1}{6}>\dfrac{1}{3}\)