\(a,\Leftrightarrow x=\dfrac{2\cdot5}{8}=\dfrac{5}{4}\\ b,\Leftrightarrow\left|x+\dfrac{1}{2}\right|=4\Leftrightarrow\left[{}\begin{matrix}x+\dfrac{1}{2}=4\\x+\dfrac{1}{2}=-4\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{2}\\x=-\dfrac{9}{2}\end{matrix}\right.\\ c,\Leftrightarrow\dfrac{5}{3}x=-\dfrac{1}{3}+\dfrac{2}{3}=\dfrac{1}{3}\Leftrightarrow x=\dfrac{1}{5}\)
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