giúp mik với, mình có mỗi 30p thôi
$a)PTHH:2Al+6HCl\to 2AlCl_3+3H_2$
$n_{Al}=\dfrac{5,4}{27}=0,2(mol)$
$\Rightarrow n_{H_2}=1,5.n_{Al}=0,3(mol)$
$\Rightarrow V_{H_2}=0,3.22,4=6,72(l)$
$b)n_{AlCl_3}=n_{Al}=0,2(mol)$
$\Rightarrow m_{AlCl_3}=0,2.133,5=26,7(g)$
$c)n_{HCl}=3n_{Al}=0,6(mol)$
$\Rightarrow m_{HCl}=0,6.36,5=21,9(g)$
pthh :
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\uparrow\)
a,
\(nAl=\dfrac{5,4}{27}=0,2mol\)
tính theo pthh: \(nH_2=\dfrac{3}{2}.nAl=\dfrac{3}{2}.0,2=0,3mol\)
\(VH_2=0,3.22,4=6,72lít\)
b,
tính theo pthh :
\(nAlCl_3=\dfrac{2}{2}.nAl=1.0,2=0,2mol\\ \Rightarrow mAlCl_3=0,2.133,5=26,7gam\)
c,
tính theo pthh :
\(nHCl=\dfrac{6}{2}.nAl=3.0,2=0,6mol\)
\(\Rightarrow mHCl=0,6.36,5=21,9gam\)
