Question

giúp mik lm 5 bài này vs ak

Answer 1

a) \(2^4+8\left[\left(-2\right)^2:\dfrac{1}{2}\right]^0-2^{-2}.4+\left(-2\right)^2\)

\(=2^4+8.1-\dfrac{1}{4}.4+4\)

\(=16+8-1+4\)

\(=24-1+4\)

\(=23+4\)

\(=27\)

Answer 2

Bài 4: 
\(8^{12}\)\(-2^{33}\)-\(2^{30}\) chia hết cho 55
= \(2^{36}\)-\(2^{33}\)-\(2^{30}\)
= \(2^{30}.\left(2^6-2^3-1\right)\)
= \(2^{30}\). 55 chia hết cho 55 (đpcm)

Answer 3

Bài 3:
Ta có: \(5^{1000}=\left(5^2\right)^{500}=25^{500}\)
\(3^{1500}=\left(3^3\right)^{500}=27^{500}\)
Do \(25^{500}< 27^{500}\Rightarrow5^{1000}< 3^{1500}\)

Answer 4

d, \(2^x+2^{x+4}=544\)
\(\Rightarrow2^x+2^x.2^4=544 \)
\(\Rightarrow2^x.\left(1+2^4\right)\)
\(\Rightarrow2^x.17=544\)
\(\Rightarrow2^x=32\)
\(\Rightarrow2^x=2^5\)\(\Leftrightarrow x=5\)