a: Thay x=16/25 vàoA, ta được:
\(A=\dfrac{4}{5}:\left(\dfrac{4}{5}+2\right)=\dfrac{4}{5}:\dfrac{14}{5}=\dfrac{2}{7}\)
b: \(B=\dfrac{1-\sqrt{x}}{\sqrt{x}\left(\sqrt{x}+1\right)}\cdot\dfrac{\left(\sqrt{x}+1\right)^2}{-\left(1-\sqrt{x}\right)}\)
\(=\dfrac{-\left(\sqrt{x}+1\right)}{\sqrt{x}}\)
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