Bài 1:
a: Ta có: \(4x-12\sqrt{x}-24\)
\(=4\left(x-3\sqrt{x}-6\right)\)
b: \(9x-1=\left(3\sqrt{x}-1\right)\left(3\sqrt{x}+1\right)\)
c: \(9x+6\sqrt{x}+1=\left(3\sqrt{x}+1\right)^2\)
d: \(x+10\sqrt{x}-24=\left(\sqrt{x}+12\right)\left(\sqrt{x}-2\right)\)
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