b) \(n_S=\dfrac{40}{32}=1,25\left(mol\right)\)
Ta có: \(n_{SO_3}=n_S=1,25\left(mol\right)\)
\(\Rightarrow m_{SO_3}=1,25\times80=100\left(g\right)\)
a) \(n_{CuSO_4}=\dfrac{480}{160}=3\left(mol\right)\)
Ta có: \(n_{Cu}=n_{CuSO_4}=3\left(mol\right)\)
\(\Rightarrow m_{Cu}=3\times64=192\left(g\right)\)
Ta có: \(n_S=n_{CuSO_4}=3\left(mol\right)\)
\(\Rightarrow m_S=3\times32=96\left(g\right)\)
\(\Rightarrow m_O=480-96-192=192\left(g\right)\)