Question

Giúp em bài u với ạ

Answer 1

u) \(\sqrt{6+2\sqrt{2}+2\sqrt{3}+2\sqrt{6}}\)

\(=\sqrt{\left(\sqrt{2}\right)^2+\left(\sqrt{3}\right)^2+1^2+2.\sqrt{2}.1+2.\sqrt{3}.1+2\sqrt{2}.\sqrt{3}}\)

\(=\sqrt{\left(\sqrt{2}+\sqrt{3}+1\right)^2}=\left|\sqrt{2}+\sqrt{3}+1\right|=\sqrt{2}+\sqrt{3}+1\)