Lần này thì đúng rồi :
\(\frac{2x}{3}+\frac{2x-1}{6}=4-\frac{x}{3}\)
\(\Leftrightarrow\frac{2x}{3}+\frac{x}{3}-\frac{1}{6}=4-\frac{x}{3}\)
\(\Leftrightarrow\frac{2x}{3}+\frac{x}{3}+\frac{x}{3}=4+\frac{1}{6}\)
\(\Leftrightarrow\frac{4x}{3}=\frac{25}{6}\)
\(\Leftrightarrow x=\frac{25}{8}\)