Ta có: \(\left\{{}\begin{matrix}\left(x-\dfrac{2}{7}\right)^{2014}\ge0\forall x\\\left(0,2-\dfrac{1}{5}y\right)^{2016}\ge0\forall y\end{matrix}\right.\)
Dấu ''='' xảy ra \(\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{7}\\y=1\end{matrix}\right.\)
\(\Rightarrow Min_H=-1\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{2}{7}\\y=1\end{matrix}\right.\)