Có: \(\dfrac{a}{3}=\dfrac{b}{3}=\dfrac{c}{4}\)
\(\Rightarrow\dfrac{a^3}{2^3}=\dfrac{b^3}{3^3}=\dfrac{c^3}{4^3}\)
\(=\dfrac{a^3}{8}=\dfrac{b^3}{27}=\dfrac{c^3}{64}\)
\(=\dfrac{a^3+b^3+c^3}{8+27+64}=\dfrac{792}{99}=8\)
\(\Rightarrow\dfrac{a^3}{8}=8\Rightarrow a^3=8.8=64\)
\(\Rightarrow a=4\)
\(\dfrac{b^3}{27}=8\Rightarrow b^3=8.27=216\)
\(\Rightarrow b=6\)
\(\dfrac{c^3}{64}=8\Rightarrow c^3=8.64=512\)
\(\Rightarrow c=8\)
Vậy giá trị của biểu thức \(H=\left|a+b-c\right|=\left|4+6-8\right|=\left|2\right|=2\)
Tick mik nha!!!
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