Ôn tập chương 1: Căn bậc hai. Căn bậc ba
Các câu hỏi tương tự
1.\(\dfrac{15\sqrt{x}-11}{x+2\sqrt{x}-3}+\dfrac{3\sqrt{x}-2}{1-\sqrt{x}}-\dfrac{2\sqrt{x}+3}{\sqrt{x}+3}\)
2.\(\dfrac{x\sqrt{x}+1}{x-1}-\dfrac{x-1}{\sqrt{x}+1}\)
3.\(\left(1-\dfrac{4}{\sqrt{x}+1}+\dfrac{1}{x-1}\right):\dfrac{x-2\sqrt{x}}{x-1}\)
4.\(\dfrac{\sqrt{x}}{\sqrt{x}+3}+\dfrac{2\sqrt{x}}{\sqrt{x}-3}-\dfrac{3x+9}{x-9}\)
Giải PT: \(\dfrac{36}{\sqrt{x-2}}+\dfrac{4}{\sqrt{y-1}}=28-4\sqrt{x-2}-\sqrt{y-1}\)
Rút gọn
Adfrac{1}{sqrt{1}-sqrt{2}}-dfrac{1}{sqrt{2}-sqrt{3}}+dfrac{1}{sqrt{3}-sqrt{4}}-...-dfrac{1}{sqrt{24}-sqrt{25}}
Bdfrac{5}{4+sqrt{11}}+dfrac{11-3sqrt{11}}{sqrt{11}-3}-dfrac{4}{sqrt{5}-1}+sqrt{left(sqrt{5}-2right)^2}
Cdfrac{sqrt{x}+1}{xsqrt[]{x}+x+sqrt{x}}:dfrac{1}{x^2-sqrt{x}} (với x0; x#1)
Ddfrac{sqrt{x^2-10x+25}}{x-5}
Đọc tiếp
Rút gọn
A=\(\dfrac{1}{\sqrt{1}-\sqrt{2}}-\dfrac{1}{\sqrt{2}-\sqrt{3}}+\dfrac{1}{\sqrt{3}-\sqrt{4}}-...-\dfrac{1}{\sqrt{24}-\sqrt{25}}\)
B=\(\dfrac{5}{4+\sqrt{11}}+\dfrac{11-3\sqrt{11}}{\sqrt{11}-3}-\dfrac{4}{\sqrt{5}-1}+\sqrt{\left(\sqrt{5}-2\right)^2}\)
C=\(\dfrac{\sqrt{x}+1}{x\sqrt[]{x}+x+\sqrt{x}}:\dfrac{1}{x^2-\sqrt{x}}\) (với x>0; x#1)
D=\(\dfrac{\sqrt{x^2-10x+25}}{x-5}\)
giải pt:
\(\dfrac{1}{2}\sqrt{x-2}-4\sqrt{\dfrac{4x-8}{9}}+\sqrt{9x+18}-5=0\)
Tìm x thỏa mãn:
\(\left(\sqrt{x}+1\right)\dfrac{\sqrt{x}+2}{\sqrt{x}+1}-\sqrt{x}-4\sqrt{x-1}+26=-6x+10\sqrt{5x}\)
Giải PT:a) dfrac{1}{2}sqrt{x-1}-dfrac{3}{2}sqrt{9x-9}+24sqrt{dfrac{x-1}{64}}-17b) sqrt{18x-9}-0,5sqrt{2x-1}+dfrac{1}{2}sqrt{25left(2x-1right)}+sqrt{49left(2x-1right)}24c) sqrt{36x-72}-15sqrt{dfrac{x-2}{25}}4left(5+sqrt{x-2}right)d) sqrt{dfrac{1}{3x+2}}-dfrac{1}{2}sqrt{dfrac{9}{3x+2}}+sqrt{dfrac{16}{3x+2}}-5sqrt{dfrac{1}{12x+8}}1e) dfrac{1}{2}sqrt{dfrac{49x}{x+2}}-3sqrt{dfrac{x}{4x+8}}-sqrt{dfrac{x}{x+2}}-sqrt{5}0
Đọc tiếp
Giải PT:
a) \(\dfrac{1}{2}\sqrt{x-1}-\dfrac{3}{2}\sqrt{9x-9}+24\sqrt{\dfrac{x-1}{64}}=-17\)
b) \(\sqrt{18x-9}-0,5\sqrt{2x-1}+\dfrac{1}{2}\sqrt{25\left(2x-1\right)}+\sqrt{49\left(2x-1\right)}=24\)
c) \(\sqrt{36x-72}-15\sqrt{\dfrac{x-2}{25}}=4\left(5+\sqrt{x-2}\right)\)
d) \(\sqrt{\dfrac{1}{3x+2}}-\dfrac{1}{2}\sqrt{\dfrac{9}{3x+2}}+\sqrt{\dfrac{16}{3x+2}}-5\sqrt{\dfrac{1}{12x+8}}=1\)
e) \(\dfrac{1}{2}\sqrt{\dfrac{49x}{x+2}}-3\sqrt{\dfrac{x}{4x+8}}-\sqrt{\dfrac{x}{x+2}}-\sqrt{5}=0\)
A=\(2\sqrt{12}-\sqrt{75}+\sqrt{\left(\sqrt{3}-2\right)^2}\)
B=\(\dfrac{x}{x-16}+\dfrac{2}{\sqrt{x}-4}+\dfrac{2}{\sqrt{x}+4}\)( Với x\(\ge\)0; x\(\ne\)16)
a) Rút gọn 2 biểu thức A, B
b) Tìm giá trị của x để B\(-\dfrac{1}{2}\)A=0
6 tháng 8 2021 lúc 19:56
Giải phương trình:1. sqrt{dfrac{42}{5-x}}+sqrt{dfrac{60}{7-x}}62. sqrt{x^2-3x+2}+sqrt{x+3}sqrt{x-2}+sqrt{x^2+2x-3}3. x^2+x+12sqrt{x+1}364. sqrt{x+2}-sqrt{x-6}25. sqrt[3]{x-1}-sqrt[3]{x-3}sqrt[3]{2}6. 5sqrt{1+x^3}2left(x^2+2right)6. left(sqrt{x+5}-sqrt{x+2}right)left(1+sqrt{x^2+7x+10}right)3
Đọc tiếp
Giải phương trình:
1. \(\sqrt{\dfrac{42}{5-x}}+\sqrt{\dfrac{60}{7-x}}=6\)
2. \(\sqrt{x^2-3x+2}+\sqrt{x+3}=\sqrt{x-2}+\sqrt{x^2+2x-3}\)
3. \(x^2+x+12\sqrt{x+1}=36\)
4. \(\sqrt{x+2}-\sqrt{x-6}=2\)
5. \(\sqrt[3]{x-1}-\sqrt[3]{x-3}=\sqrt[3]{2}\)
6. \(5\sqrt{1+x^3}=2\left(x^2+2\right)\)
6. \(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(1+\sqrt{x^2+7x+10}\right)=3\)
Giải phương trình vô tỉ:
1) \(8x^2+\sqrt{\dfrac{1}{x}}=\dfrac{5}{2}\)
2) \(x^2+2x+4=3\sqrt{x^3+4x}\)
3) \(\sqrt{\dfrac{x^3}{3-4x}}-\dfrac{1}{2\sqrt{x}}=\sqrt{x}\)
4) \(\sqrt{\dfrac{5\sqrt{2}+7}{x+1}}+4x=3\sqrt{2}-1\)
Giải phương trình
\(a.\dfrac{3}{4}\sqrt{4x}-\sqrt{4x}+5=\dfrac{1}{4}\sqrt{4x}\)
\(b.\sqrt{3-x}-\sqrt{27-9x}+1,25.\sqrt{48-16x}=6\)
\(c.\dfrac{5\sqrt{x}-2}{8\sqrt{x}+2,5}=\dfrac{2}{7}\)
\(d.\sqrt{9x^2+12x+4}=4\)