Đk: x >/ 1
\(\sqrt{x+2\sqrt{x-1}}+\sqrt{x+2\sqrt{x-1}}=2\)
\(\Leftrightarrow2\left|\sqrt{x-1}+1\right|=2\Leftrightarrow\left|\sqrt{x-1}+1\right|=1\)
\(\Leftrightarrow\left[{}\begin{matrix}\sqrt{x-1}+1=1\\\sqrt{x-1}+1=-1\left(vn\right)\end{matrix}\right.\) \(\Leftrightarrow x=1\left(N\right)\)
Kl: x=1