Bài 3 :
\(\left|x-1\right|-10=2x+7\)
\(\Leftrightarrow\left|x-1\right|=2x+17\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=2x+17\\x-1=-2x-17\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=-18\\x=\frac{-16}{3}\end{matrix}\right.\)
Tìm GTNN :
\(B=\left|2x-4\right|+5\ge5\forall x\)
Dấu "=" \(\Leftrightarrow x=2\)
giải pt:
a) x^5 + 2x^4 + 3x^3 + 3x^2 + 2x +1=0
b) x^4 + 3x^3 - 2x^2 + x - 3 = 0
Bài 1: giải pt
a, \(\frac{4}{x-2}\)+ \(\frac{1}{x+3}\)=0
Bài2 giải bất pt và biểu diễn trên truc số
a, 3x(2x+1)+4<2x(3x-1)-6 b, (2x-3)\(^2\)<(2x+5)(2x-5)
giúp mk nha
giải pt: a. (x - 2)(x+1)(x+3) = (x+3)(x+1)(2x-5)
b. \(5+\frac{96}{x^2-16}=\frac{2x-1}{x+4}+\frac{3x-1}{x-4}\)
giải pt 5(x-1)+2/6-7x-1/4=2(2x+1)/7-5
1,Giải Pt
a,\(\frac{3x-7}{2}+\frac{x+1}{3}=-16\)
b,\(x-\frac{x+1}{3}=\frac{2x+1}{5}\)
c,\(\frac{7-3x}{12}+\frac{3}{4}=2\left(x-2\right)+\frac{5\left(5-2x\right)}{6}\)
e,\(\frac{3\left(x+3\right)}{4}+\frac{1}{2}=\frac{5x+9}{3}-\frac{7x-9}{4}\)
Giải các pt sau:
a)|x-2|=3.
b)|x-3|=2x-5
c) |-2x|=3x+4
giải pt
1,\(\frac{1}{x-1}+\frac{2x^2-5}{x^3-1}=\frac{4}{x^2+x+1}\)
2,\(\frac{x+4}{2x^2-5x+2}+\frac{x+1}{2x^2-7x+3}=\frac{2x+5}{2x^2-7x+3}\)
3,\(\frac{x+1}{x-1}-\frac{x-1}{x+1}=3x\left(1-\frac{x-1}{x+1}\right)\)
4,\(\frac{2x}{x-1}+\frac{4}{x^2+2x-3=}=\frac{2x-5}{x+3}\)
5,\(\frac{1}{x-1}-\frac{7}{x+2}=\frac{3}{x^2+x-2}\)
6,\(\frac{x+3}{x-4}+\frac{x-1}{x-2}=\frac{2}{6x-8-x^2}\)
7,\(\frac{1}{x-1}-\frac{7}{x+2}=\frac{3}{1-x^2}\)
Bài 1 : Giải pt:
a. \(\frac{2x+1}{3}\) - \(\frac{x}{4}\) = 2
b. \(\frac{2x+5}{2x}\) - \(\frac{x}{x+5}\) = 0
