Question

giải phương trình

\(\sqrt{3x}\)-2\(\sqrt{12x}\)+\(\dfrac{1}{2}\sqrt{27x}\)= -4

Answer 1

\(\Leftrightarrow\sqrt{3x}-4\sqrt{3x}+\dfrac{3}{2}\sqrt{3x}=-4\)

\(\Leftrightarrow\sqrt{3x}\cdot\dfrac{-3}{2}=-4\)

\(\Leftrightarrow\sqrt{3x}=4:\dfrac{3}{2}=\dfrac{8}{3}\)

=>3x=64/9

=>x=64/27

Answer 2

`-> sqrt(3x) - 4 sqrt(3x) + 3/2 sqrt(3x) = -4`

`-> sqrt(3x) . -3/2 = -4`

`-> sqrt (3x) = -4 : -3/2`

`-> sqrt(3x) = 8/3`

`-> 3x = 64/9`

`-> x = 64/27`