Question

Giải phương trình:

Answer 1

\(6x^4-7x^2+1=0\\ \Leftrightarrow6x^4-6x^2-x^2+1=0\\ \Leftrightarrow6x^2\left(x^2-1\right)-\left(x^2-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+1\right)\left(6x^2-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-1\\x=\dfrac{\sqrt{6}}{6}\end{matrix}\right.\)

Answer 2

7) 6x⁴-7x²+1=0

=>6x⁴-6x²-1x²+1=0

=>(6x⁴-6x²)-(1x²-1)=0

=>6x²(x²-1)-1.(x²-1)=0

=>(6x²-1).(x²-1)=0

=>(6x²-1)(x-1)(x+1)=0

=>(6x²-1)=0

=>x-1=0

=>x+1=0

tự tính ra kq nha