( x - 2 )2 = 25
=> ( x - 2 )2 = 52
=> x - 2 = 5
=> x = 5 + 2
=> x = 7
Ta có: \(\left(x+2\right)^2=25\)
=> \(\left(x+2\right)^2=5^2\)
\(=>x+2=5\)
\(=>x=5-2=3\)
Vậy x=3
Ta có:
\(\left(x-2\right)^2=25\)
\(\left(x-2\right)^2=5^2\)
\(\Rightarrow x-2=5\)
\(x=5+2\)
\(x=7\)
( x - 2 )2 = 25
<=> ( x - 2 )2 = 52
<=> x - 2 = 5
<=> x = 7