\(\dfrac{\left(5x+6\right)20}{140}\) -\(\dfrac{\left(3x+1\right)35}{140}\)=\(\dfrac{\left(x+16\right)28}{140}\)
=> (5x+6).20-(3x+1).35 = (x+16).28
<=>100x+120-(105x+35) = 28x+448
<=>100x+120-105x-35 = 28x+448
<=>100x-105x-28x = -120+35+448
<=> -33x = 363 <=> x = -11