\(\dfrac{1}{x}+\dfrac{1}{\left(x+1\right)^2}=15\)
\(\Rightarrow\dfrac{x^2+2x+1}{x\left(x+1\right)^2}+\dfrac{x}{x\left(x+1\right)^2}=15\)
\(\Rightarrow\dfrac{x^2+3x+1}{x\left(x+1\right)^2}=15\)
\(\Rightarrow x^2+3x+1=15x\left(x^2+2x+1\right)\)
\(\Rightarrow x^2+3x+1=15x^3+30x^2+15x\)
\(\Rightarrow15x^3+29x^2+12x+1=0\)
Phân tích thành nhân tử là tìm được x :)))