a) \(\sqrt{\left(x+1\right)^2}=2\)
\(\Leftrightarrow\left(x+1\right)^2=2^2\)
\(\Leftrightarrow x+1=2\)
\(\Leftrightarrow x=1\)
Vậy ...
b) \(\sqrt{9\left(2x+1\right)^2}=3\)
\(\Leftrightarrow9\left(2x+1\right)^2=3^2\)
\(\Leftrightarrow9\left(4x+1\right)=9\)
\(\Leftrightarrow4x+1=1\)
\(\Leftrightarrow4x=0\)
\(\Leftrightarrow x=0\)
Vậy ...
c) \(\sqrt[2]{}\) là \(\sqrt{ }\) á
\(\sqrt{\left(x+1\right)^2}=0\)
\(\Leftrightarrow\left(x+1\right)^2=0^2\)
\(\Leftrightarrow x+1=0\)
\(\Leftrightarrow x=0-1=-1\)
Vậy ......
d) \(\sqrt{\left(x-1\right)^2}=-1\)
\(\Leftrightarrow\left(x-1\right)^2=\left(-1\right)^2\)
\(\Leftrightarrow x-1=1\)
\(\Leftrightarrow x=1+1=2\)
Vậy ....
Câu d mk k chắc lắm
