a) ĐK: x>=-2
=> \(\sqrt{x+5}+\sqrt{x+2}>0\)
Nhân liên hợp:
\(\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(\sqrt{x+5}-\sqrt{x+2}\right)\left(1+\sqrt{x^2+7x+10}\right)=3\)
<=> \(\left(x+5-x-2\right)\left(1+\sqrt{x^2+7x+10}\right)=3\)
<=> \(3\left(1+\sqrt{x^2+7x+10}\right)=3\)
<=>1+\(\sqrt{\left(x+5\right)\left(x+2\right)}=1\)
<=> \(\sqrt{\left(x+5\right)\left(x+2\right)}=0\)
<=> (x+5) (x+2) =0
<=> x=-5 hoac x=-2
-Do x>= -2.
Vay x=-2