b: \(\Leftrightarrow\sqrt{x-3}\left(\sqrt{x+3}-3\right)=0\)
=>x-3=0 hoặc x+3=9
=>x=3 hoặc x=6
c: \(\Leftrightarrow\sqrt{x^3-6x^2+9}=2x-6=\sqrt{4x^2-24x+36}\)
\(\Leftrightarrow x^3-6x^2+9-4x^2+24x-36=0\)
=>\(x^3-10x^2+24x-27=0\)
hay \(x\in\left\{7.18\right\}\)