Lời giải:
PT(1):
\(3m^2-2m-13=0\)
\(\Leftrightarrow 3(m^2-\frac{2}{3}m+\frac{1}{3^2})-\frac{40}{3}=0\)
\(\Leftrightarrow 3(m-\frac{1}{3})^2=\frac{40}{3}\Leftrightarrow (m-\frac{1}{3})^2=\frac{40}{9}\)
\(\Rightarrow \left[\begin{matrix} m-\frac{1}{3}=\frac{\sqrt{40}}{3}\\ m-\frac{1}{3}=\frac{-\sqrt{40}}{3}\end{matrix}\right.\Leftrightarrow \left[\begin{matrix} m=\frac{1+\sqrt{40}}{3}\\ m=\frac{1-\sqrt{40}}{3}\end{matrix}\right.\)
PT(2):
\(2m-2+1=0\)
\(\Leftrightarrow 2m-1=0\Leftrightarrow m=\frac{1}{2}\)