ĐKXĐ: \(x\ge\dfrac{1}{2}\)
\(pt\Leftrightarrow\left(3\sqrt{2x-1}\right)^2=\left(5-2x\right)^2\)
\(\Leftrightarrow9\left(2x-1\right)=25-20x+4x^2\)
\(\Leftrightarrow-4x^2+38x-34=0\)
\(\Leftrightarrow-4x^2+4x+34x-34=0\)
\(\Leftrightarrow-4x\left(x-1\right)+34\left(x-1\right)=0\)
\(\Leftrightarrow\left(x-1\right)\left(-4x+34\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x-1=0\\-4x+34=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=1\\x=\dfrac{17}{2}\end{matrix}\right.\)(tm)
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