Câu 2:
a: \(\sqrt{9x-9}+1=7\)
\(\Leftrightarrow3\sqrt{x-1}=6\)
\(\Leftrightarrow x-1=4\)
hay x=5
b: \(\sqrt{9x+27}-\dfrac{1}{4}\sqrt{16x+48}+\sqrt{x+3}=9\)
\(\Leftrightarrow\sqrt{x+3}=3\)
hay x=6
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