\(\dfrac{3.3}{20.23}+\dfrac{3.3}{23.26}+...+\dfrac{3.3}{77.80}\)
\(=3\left(\dfrac{3}{20.23}+\dfrac{3}{23.26}+...+\dfrac{3}{77.80}\right)\)
\(=3\left(\dfrac{1}{20}-\dfrac{1}{23}+\dfrac{1}{23}-\dfrac{1}{26}+...+\dfrac{1}{77}-\dfrac{1}{80}\right)\)
\(=3\left(\dfrac{1}{20}-\dfrac{1}{80}\right)\)
\(=3.\dfrac{3}{80}=\dfrac{9}{80}< 1\left(đpcm\right)\)
Vậy...