ĐKXĐ: \(x^2+4x-3\ge0\)
\(\Leftrightarrow x^2+4x+4\ge7\)
\(\Leftrightarrow\left(x+2\right)^2\ge7\)
\(\Leftrightarrow\left|x+2\right|\ge\sqrt{7}\)
\(\Leftrightarrow\left[{}\begin{matrix}x+2\ge\sqrt{7}\\x+2\le-\sqrt{7}\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x\ge-2+\sqrt{7}\\x\le-2-\sqrt{7}\end{matrix}\right.\)