Question

Giải giúp ạ e cần gấp

Answer 1

đkxđ : x khác 7 , x khác 5/2

\(\Leftrightarrow\dfrac{\left(3x-2\right)\left(2x-5\right)}{\left(x-7\right)\left(2x-5\right)}-\dfrac{\left(6x+1\right)\left(x-7\right)}{\left(2x-5\right)\left(x-7\right)}=0\)

<=> \(\dfrac{6x^2-15x-4x+10}{....}-\dfrac{6x^2-42x+x-7}{...}=0\)

<=> \(6x^2-19x+10-6x^2+41x+7=0\)

<=> 22x + 17 =0

<=> \(x=-\dfrac{17}{22}\) (tm)

Vậy..

Answer 2