Question

giá trị x thỏa mãn | x - 6 |+2x = 10

Answer 1

TH1:x-6+2x=10

3x-6=10

3x=16

x=\(\frac{16}{3}\)

TH2:-(x-6)+2x=10

6-x+20=10

26-x=10

x=16

Answer 2

Ta có: \(\left|x-6\right|+2x=10\)

\(\Rightarrow\left|x-6\right|=10-2x\)

\(\Rightarrow x-6=\pm\left(10-2x\right)\)

+) \(x-6=10-2x\)

\(\Rightarrow3x=16\)

\(\Rightarrow x=\frac{16}{3}\)

+) \(x-6=-\left(10-2x\right)\)

\(\Rightarrow x-6=-10+2x\)

\(\Rightarrow-x=-4\)

\(\Rightarrow x=4\)

Vậy \(x\in\left\{\frac{16}{3};4\right\}\)