\(A=\left(4567-97\right)+\left(-1075\right)-4567-\left(29-1075\right)\)
\(A=4567-97-1075-4567-29+1075\\ A=\left(4567-4567\right)+\left[\left(-1075\right)+1075\right]-97-29\\ A=0+0-97-29\\ A=0-97-29\\ A=-97-29\\ A=-126\)
gia tri bieu thuc A=1/3+1/3^2
tap hop cac so nguyen x de bieu thuc a=l x+2l + l 1-xl dat gia tri nho nhat
bai 1. 11/3.40/13+37/5:7/33-(11/13.1/3+33/7:5/2)
bai 2.tim x
a,3.(x-1)-5.(-7)=(-2)^3-2x
b,2./(1-x)^2+1/-2^2.3=8
bai 3,cho bieu thuc
M=n+1/n+1 - 3-8n/n+1 + 8/n+1
tim cac gia tri cua n de bieu thuc M co gia tri la so nguyen
bai 4,So hoc sinh cua 1 truong ko qua 1000 em,neuxeptoan bo so hoc sinh cua truong do thanh cac hang,moi hang 20 nguoi thi con thieu 5 nguoi,neu xep moi hang 25 nguoi hoac 30 nguoi thi deu thua 15 nguoi , neu xep 42 hang thi vua du . hoi truong do co bao nhieu hoc sinh
bai 5,cho bieu thuc
A=2+2^2+...+2^200
c/m rang
a, A+2 la 1 luy thua cua 2
b, Achia het cho 30
c,A co phai la so chinh phuong ko ? vi sao ?
bai 6,cho 2 bieu thuc
A=1/1+2 + 1/1+2+3 + ...1/1+2+3+...+99
B=1 + 1/2^2+1/3^2 + ...+1/49^2
c/m rang A<B
1.goi A la tap hop cac so tu nhien co 2 chu so chia het cho 5 .Tong cac phan tu la:
2Gia tri nho nhat cua bieu thuc A=(x^2+2)^2 labài 1: Tính hợp lí
a) 666-(-422)-100+88 b) 4567+(-6789)+369-567
c) (2018-119+29)-(-119+29)
d) \(\frac{7}{19}\)\(.\) \(\frac{8}{11}\)\(+\)\(\frac{7}{19}\)\(.\)\(\frac{3}{11}\)\(-\)\(\frac{26}{19}\)
e) \(\frac{318}{241}\)\(.\)\(\frac{512}{743}\)\(-\)\(\frac{318}{241}\)\(.\)\(\frac{512}{743}\)
tìm so tu nhien nho nhat cua bieu thuc b=2003-1003/999-x
số các số nguyên của n thỏa mãn de bieu thuc : A = \(\frac{3n+4}{n-1}\)có giá trị nguyên
tim gia tri nho nhat
A=/x+1/+/x+2/+/x+3/
B=/x-2017/+/x-2018/+/x-2019/
gia tri tuyet doi cua 2x-1<hoac= 4
