\(\frac{a}{3}=\frac{2a+2}{5}\)
\(\Rightarrow3\left(2a+2\right)=5a\)
\(\Rightarrow6a+6=5a\)
\(\Rightarrow a=6\)
Vậy a = 6
Ta có: \(\frac{a}{3}=\frac{2a+2}{5}\)
=> 5a=3(2a+2)
=> 5a=6a+6
=> 6=5a-6a
=> 6=-a
=> a=-6
Vậy a=-6
\(\frac{a}{3}=\frac{2a+2}{5}\)a
\(\frac{a}{3}=\frac{2a+2}{5}\)
\(\Rightarrow5a=6a+6\)
\(5a-6a=6\)
\(-a=6\)
\(\Rightarrow a=-6\)
ta có a/3 = 2a + 2 / 5
=> 5a = 3(2a + 2)
=> 5a = 6a + 6
=> 5a - 6a = 6
=> -a = 6
=> a= -6
Vậy a = -6