\(\frac{5}{9}-1^2_9x=\frac{2}{3}-\frac{15}{9}z\)
\(\frac{15}{9}x-\frac{11}{9}x=\frac{2}{3}-\frac{5}{9}\)
\(\frac{4}{9}x=-\frac{1}{9}\)
\(x=-\frac{1}{4}\)
\(\frac{5}{9}-1^2_9x=\frac{2}{3}-\frac{15}{9}z\)
\(\frac{15}{9}x-\frac{11}{9}x=\frac{2}{3}-\frac{5}{9}\)
\(\frac{4}{9}x=-\frac{1}{9}\)
\(x=-\frac{1}{4}\)
giá trị x thoã mãn:
\(\frac{x}{2}+\frac{x}{4}+\frac{x}{2016}=\frac{x}{3}+\frac{x}{5}+\frac{x}{2017}\) là x =...
1) tìm x biết
a) \(\left(\frac{2}{3}\right)^x=\left(\frac{4}{9}\right)^{50}\)
b) \(\left(\frac{2}{3}-x\right)^2=\frac{1}{36}\)
c)\(\left(x-\frac{1}{2}\right)^{50}-\left(\frac{1}{3}\right)^{20}\times\left(-\frac{1}{9}\right)^{15}\)
2) chứng tỏ
\(\left(74^{m+1}+74^m\right)⋮25\)
Cho \(\frac{x+y}{3}=\frac{5-z}{1}=\frac{y+z}{2}=\frac{9+y}{5}\)
a) Tìm x
b) Tìm x+y+z
tìm x
\(4\frac{5}{9}:2\frac{5}{18}-7< x< \left(3\frac{1}{5}:3,2+4,5\times1\frac{31}{45}\right):\left(-21\frac{1}{2}\right)\)
tìm x,y,z
\(\frac{x-1}{5}=\frac{y-2}{3}=\frac{z-2}{2}\)và 3x-5y+6z=9
Tìm x, y , z
\(\frac{x+1}{3}=\frac{y-2}{5}=\frac{2z+14}{9}\) và x + z = y
\(b.\left|\frac{3}{2}x+\frac{1}{9}\right|+\left|\frac{1}{5}y-\frac{1}{2}\right|\le0\)
tìm x,y
a\(\frac{2x+1}{5}=\frac{4y-5}{9}=\frac{2x+4y-4}{7x}\)
b, \(\frac{x+4}{6}=\frac{3y-1}{8}=\frac{3y-x-5}{x}\)
c, \(\frac{x+1}{3}=\frac{y-2}{5}=\frac{2z+14}{9}\)và x + z = y
Tìm x,y,z:
a)\(\frac{x}{3}=\frac{y}{4};\frac{x}{5}=\frac{z}{6}\)và x+y-z=3
b)(x-1):\(2\frac{1}{3}\)=\(6\frac{9}{11}\):(x-1)