a, Để A \(\in Z\Leftrightarrow3⋮x-1\)
=> x - 1 \(\inƯ\left(3\right)=\left\{\pm1;\pm3\right\}\)
=> x = 2; 0; 4; -2 (thỏa mãn)
b, Để B \(\in Z\Leftrightarrow x-2⋮x+3\)
Có x + 3 \(⋮x-3\)
<=> x - 2 - x - 3 \(⋮x-3\)
<=> -5 \(⋮x-3\)
=> x - 3 \(\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)
=> x = 4; 2; 8; -2 (thỏa mãn)
@đỗ thùy linh
c, Để C \(\in Z\Leftrightarrow2x+1⋮x-3\)
Có 2(x - 3) \(⋮x-3\)
<=> 2x + 1 - 2x + 6 \(⋮x-3\)
<=> 7 \(⋮x-3\)
=> x - 3 \(\inƯ\left(7\right)=\left\{\pm1;\pm7\right\}\)
=> x = 4; 2; 10; -5 (thỏa mãn)
@đỗ thùy linh