\(\frac{x-3}{x+5}=\frac{5}{7}\)
7(x - 3) = 5(x + 5)
7x - 21 = 5x + 25
7x - 5x = 25 + 21
2x = 46
x = 46 : 2
x = 23
Ta có : \(\frac{x-3}{x+5}=\frac{5}{7}\left(x\ne-5\right)\)
\(\Leftrightarrow\left(x-3\right).7=\left(x+5\right).5\)
\(\Leftrightarrow7x-21=5x+25\)
\(\Leftrightarrow7x-5x=25+21\)
\(\Leftrightarrow2x=46\)
\(\Leftrightarrow x=23\)