Question

\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{24}+\frac{1}{48}+\frac{1}{28}\)

Answer 1

\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{24}+\frac{1}{48}+\frac{1}{28}\)

=> \(\left(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}\right)+\left(\frac{1}{24}+\frac{1}{48}\right)+\frac{1}{28}\)

=> \(\left(\frac{4}{16}+\frac{2}{16}+\frac{1}{16}\right)+\left(\frac{2}{48}+\frac{1}{48}\right)+\frac{1}{28}\)

=> \(\frac{7}{16}+\frac{3}{48}+\frac{1}{28}\)

=> \(\frac{1}{2}+\frac{1}{28}=>\frac{14}{28}+\frac{1}{28}=\frac{15}{28}\)

Answer 2

đúng 100%

Answer 3

\(\frac{1}{4}\)+\(\frac{1}{8}\)+\(\frac{1}{16}\)+\(\frac{1}{24}\)+\(\frac{1}{48}\)+\(\frac{1}{28}\)

=\(\frac{3}{8}\)+ \(\frac{1}{16}\)+\(\frac{1}{24}\)+\(\frac{1}{48}\)+\(\frac{1}{28}\)

=\(\frac{7}{16}\)+\(\frac{1}{24}\)+\(\frac{1}{48}\)+\(\frac{1}{28}\)

=\(\frac{23}{48}\)+\(\frac{1}{48}\)+\(\frac{1}{28}\)

=\(\frac{24}{48}\)+\(\frac{1}{28}\)

=\(\frac{1}{2}\)+\(\frac{1}{28}\)

=\(\frac{15}{28}\)