Ôn tập toán 8
Các câu hỏi tương tự
Đề bài : CHứn minh các biểu thức sau không phụ thuộc vào x :
(4x-1)3 - (4x-3)(16x2+3)\(\frac{\left(x+5\right)^2+\left(x-5\right)^2}{x^2+25}\)\(\frac{\left(2x+5\right)^2+\left(5x-2\right)^2}{x^2+1}\)
a) \(16x-5x^2-3\)
b) \(2x^2+7x+5\)
c) \(4x^4+4x^3-x^2-x\)
d) \(x^6-x^4-9x^3+9x^2\)
e) \(x^4-4x^3+8x^2-16x+16\)
g) \(\left(x+1\right)\left(x+2\right)\left(x+4\right)\left(x+4\right)-15\)
Tim x
a) \(\left(4x+3\right).\left(4x-3\right)-\left(4x-5\right)^2=46\)
b) \(\left(x+1\right)^3+2x-\left(x-1\right)^3-3.\left[\left(x+1\right)^2+\left(x-1\right)^2\right]+5=0\)
\(\left[\frac{1}{\left(2x-y\right)^2}+\frac{2}{4x^2-y^2}+\frac{1}{\left(2x+y\right)^2}\right].\frac{4x^2+4xy+y^2}{16x}\)
Tìm x biết:
\(\left(12x-5\right)\left(4x-1\right)+\left(3x-7\right)\left(1-16x\right)=81\)
Mình đăng giùm chị mình thôi!
tìm x biết :
\(\frac{1}{\left(x-1\right)x}+\frac{1}{\left(x-2\right)\left(x-1\right)}+\frac{1}{\left(x-3\right)\left(x-2\right)}+\frac{1}{\left(x-4\right)\left(x-3\right)}=\frac{x}{x^2-4x}\)
Phân tích:
a, \(x^6-x^4-9x^3+9x^2\)
b, \(x^4-4x^3+8x^2-16x+16\)
c, \(\left(xy+4\right)^2-4\left(x+y\right)^2\)
d, \(\left(a+b+c\right)^2+\left(a-b+c\right)^2-4b^2\)
Tim x
a) \(\left(x+3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right).\left(4x^2-2x+1-3x^2\right)=54\)
b) \(\left(x-3\right)^3-\left(x-3\right).\left(x^2+3x+9\right)+6.\left(x+1\right)^2+3x^2=-33\)
Tìm x
\(\left(x-3\right)^3-x.\left(3x+1\right)^2+\left(2x+1\right).\left(4x^2-2x+1-3x^2\right)\)