2M + nCl2 \(\rightarrow\) 2MCln
n M = \(\dfrac{0,03375}{M}\) (mol)
n MCln = \(\dfrac{0,166875}{M+35,5n}\) (mol)
Theo PTHH : n M = n MCln
\(\Leftrightarrow\) \(\dfrac{0,03375}{M}\) = \(\dfrac{0,166875}{M+35,5n}\)
\(\Leftrightarrow\) 0,166875M = 0,03375M + 1,198125n
\(\Leftrightarrow\) 0,133125M = 1,198125n
\(\Leftrightarrow\) M = 9n