MA=15.2=30\(\rightarrow n_A=\dfrac{7,5}{15}=0,5mol\)
\(n_{CO_2}=\dfrac{22}{44}=0,5mol\rightarrow n_C=n_{CO_2}=0,5mol\)
\(n_{H_2O}=\dfrac{13,5}{18}=0,75mol\rightarrow n_H=2n_{H_2O}=1,5mol\)
\(n_C:n_H=0,5:1,5=1:3\)
-Công thức nguyên: (CH3)n
-Ta có: 15n=30\(\rightarrow\)n=2\(\rightarrow\)CTHH: C2H6