Tự tóm tắt ...
------------------------------------------------------------------
Theo bài ra : \(I_1-I_2=0,6I_1=>I_2=0,4I_1\)
Mà ta có :
\(\dfrac{U_1}{U_2}=\dfrac{I_1}{I_2}\)
\(\Leftrightarrow\dfrac{12}{U_2}=\dfrac{I_1}{0,4I_1}\)
\(\Leftrightarrow\dfrac{12}{U_2}=\dfrac{5}{2}=>U_2=\dfrac{24}{5}=4,8\left(V\right)\)
Vậy ...