\(C_6H_{12}O_6\underrightarrow{t^o,xt}2C_2H_5OH+2CO_2\)
\(n_{C_2H_5OH}=\dfrac{230}{46}=5\left(kmol\right)\)
Theo PT: \(n_{C_6H_{12}O_6\left(LT\right)}=\dfrac{1}{2}n_{C_2H_5OH}=2,5\left(kmol\right)\)
Mà: H = 60%
\(\Rightarrow n_{C_6H_{12}O_6\left(TT\right)}=\dfrac{2,5}{60\%}=\dfrac{25}{6}\left(kmol\right)\)
\(\Rightarrow m_{C_6H_{12}O_6\left(TT\right)}=\dfrac{25}{6}.180=750\left(kg\right)\)
\(n_{C_2H_5OH}=\dfrac{230}{46}=5\left(mol\right)\)
PTHH :
\(C_6H_{12}O_6\underrightarrow{lenmen}2C_2H_5OH+2CO_2\uparrow\)
2,5 0,5
\(m_{C_6H_{12}O_6\left(lt\right)}=2,5.180=450\left(g\right)\)
\(m_{C_6H_{12}O_6\left(tt\right)}=\dfrac{450.100}{60}=750\left(g\right)\)
