đặt ...là x
a,\(\dfrac{1}{2}+x=\dfrac{-2}{3}\)
\(x=\dfrac{-2}{3}-\dfrac{1}{2}\)
\(x=\dfrac{-4-3}{6}=\dfrac{-7}{6}\)
\(b,\dfrac{-1}{3}+x=\dfrac{2}{5}\)
\(x=\dfrac{2}{5}-\dfrac{-1}{3}=\dfrac{11}{15}\)
\(c,\dfrac{1}{4}-x=\dfrac{1}{20}\)
\(x=\dfrac{1}{4}-\dfrac{1}{20}=\dfrac{1}{5}\)
\(d,\dfrac{-8}{13}-x=0\)
\(x=\dfrac{-8}{13}-0=\dfrac{-8}{13}\)
nàng hãy cố gắng luyện tập thêm nha