\(\Leftrightarrow\left[{}\begin{matrix}\dfrac{4}{3}x-\dfrac{1}{2}=\dfrac{2}{3}\\\dfrac{4}{3}x-\dfrac{1}{2}=-\dfrac{2}{3}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}\dfrac{4}{3}x=\dfrac{7}{6}\\\dfrac{4}{3}x=-\dfrac{1}{6}\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{7}{8}\\x=-\dfrac{1}{8}\end{matrix}\right.\)
\(\left(\dfrac{4}{3}x-\dfrac{1}{2}\right)^2=\dfrac{4}{9}\)
\(\left(\dfrac{4}{3}x-\dfrac{1}{2}\right)^2\)=\(\left(\dfrac{2}{3}\right)^2\)
\(\dfrac{4}{3}x-\dfrac{1}{2}\)=\(\dfrac{2}{3}\)
\(\dfrac{4}{3}x=\)\(\dfrac{7}{6}\)
x=\(\dfrac{7}{8}\)
