\(\dfrac{2\sqrt{2}+\sqrt{6}}{4+\sqrt{24}}=\dfrac{\sqrt{2}\left(2+\sqrt{3}\right)}{\sqrt{2}\left(2\sqrt{2}+\sqrt{12}\right)}=\dfrac{2+\sqrt{3}}{2\sqrt{2}+2\sqrt{3}}\)
\(=\dfrac{2+\sqrt{3}}{2\left(\sqrt{3}+\sqrt{2}\right)}=\dfrac{\left(2+\sqrt{3}\right)\left(\sqrt{3}-\sqrt{2}\right)}{2}\)
\(=\dfrac{2\sqrt{3}-2\sqrt{2}+3-\sqrt{6}}{2}\)